The Zeroes Of The Quadratic Polynomial X2+99X+127 Are

The Zeroes Of The Quadratic Polynomial X2+99X+127 Are
the zero of the quadratic polynomial x^2+99x+127 are a both positive b from brainly.com

The Zeroes of the Quadratic Polynomial x2+99x+127 are

What is a Quadratic Polynomial?

A quadratic polynomial is a polynomial of degree two, which can be written in the form ax2+bx+c, where a, b, c are the coefficients and x is the variable. The quadratic equation is a special case of a polynomial equation of degree two.

What are the Zeroes of a Quadratic Polynomial?

The zeroes of a quadratic polynomial are the values of x for which the polynomial is equal to zero. In other words, the zeroes of a quadratic polynomial are the solutions to the equation ax2+bx+c=0.

What are the Zeroes of x2+99x+127?

The zeroes of x2+99x+127 are the values of x that make the expression equal to zero. In this case, the equation is x2+99x+127=0. To find the zeroes of this equation, we must solve for x. To do this, we can use the quadratic formula, which is x = (-b ± √b2 – 4ac)/2a.

Plugging in the values for a, b, and c in our equation, we find that x = (-99 ± √992 – 4(1)(127))/2(1). This simplifies to x = (-99 ± √9900)/2 or x = (-99 ± 100)/2. Solving for x, we find that the zeroes of x2+99x+127 are -49 and -2.

Conclusion

In conclusion, the zeroes of the quadratic polynomial x2+99x+127 are -49 and -2. This can be found by solving the equation using the quadratic formula.

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